(t-(1)/(6))^(2)=-(17)/(36)

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Solution for (t-(1)/(6))^(2)=-(17)/(36) equation: 



(t-(1)/(6))^(2)=-(17)/(36)

We move all terms to the left:

(t-(1)/(6))^(2)-(-(17)/(36))=0

We add all the numbers together, and all the variables

(+t-1/6)^2-(-17/36)=0

We get rid of parentheses

(+t-1/6)^2+17/36=0

We calculate fractions


((+t-1*36)/()+()/()=0



We calculate terms in parentheses: +((+t-1*36)/()+()/(), so:

(+t-1*36)/()+()/(

We add all the numbers together, and all the variables

(t-36)/()+()/(

We add all the numbers together, and all the variables

(t-36)/()+1

We multiply all the terms by the denominator


(t-36)+1*()

We add all the numbers together, and all the variables

(t-36)

We get rid of parentheses

t-36

Back to the equation:

+(t-36)



We get rid of parentheses

t-36=0

We move all terms containing t to the left, all other terms to the right

t=36

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